<<<<<< TIME POSE SUBROUTINE >>>>>>>>>

PAUSE

If they want to quit, do so

    <<<<<< 4 BOTTOM LINES CLEANING SUBROUTINE >>>>>>

ENCORE5

    <<<<<< REVIEW CLEANING SUBROUTINE >>>>>>

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BOX

                        SOLUTION                        

GO

 Let us write a shell script for counting

 the number of .c, .o, and .a files.

 This process will consist of the following steps:

        1. Initialize the .c, .o and .a counters

        2. Count the number of .c files

        3. Count the number of .o files

        4. Count the number of .a files

        5. Print the number of each type of files!

 Step 1, initialize the three counters to 0.

    c_count=0; o_count=0; a_count=0

 Start the iteration for each of three types.

    for i in .c .o .a

    do

 Start iteration for each file type.

      for k in *$i*

      do

 Start counting the number of .c files.  Note expr 

 is a built-in shell function for evaluating mathematical expressions.

          if [ "$i" = .c ]

          then

             c_count=`expr $c_count + 1`

          fi

 In a similar fashion, count the number of .o and .a files.

          if [ "$i" = .o ]

          then

             o_count=`expr $o_count + 1`

          fi

          if [ $i = ".a" ]

          then

             a_count=`expr $a_count + 1`

          fi

 Finally, end the loops, and print the results!

       done

    done

    echo the number of .c files is $c_count

    echo the number of .o files is $o_count

    echo the number of .a files is $a_count

 <CR> - to continue