<<<<< TERMINAL SCREEN DRAWING SUBROUTINE >>>>>>>>

UTERMINAL

                    TERMINAL                  

NEXT

 $V1$

     <<<<<< TIME POSE SUBROUTINE >>>>>>>>>

PAUSE

If they want to quit, do so

    <<<<<< 4 BOTTOM LINES CLEANING SUBROUTINE >>>>>>

BOTCLEAN

If they want to quit, do so

ENCORE5

    <<<<<< REVIEW CLEANING SUBROUTINE >>>>>>

CLEAN

If they want to quit, do so

ENCORE

    <<<<<< CLEAN THE INSIDE OF BOUNDED ARE ONLY >>>>>

BOX

                         COMMAND                       

GO

  grep

 SYNTAX

          grep  [-options]  expression [files]

 FUNCTION

          grep searches the input file for lines containing

          the expression.

 SOME OPTIONS: 

       -v  -  all lines are printed except those with matching text

       -l  -  only the names of files with matching lines

              are listed, with each name on a new line

       -n  -  prints the line number along with the line

               containing the matching pattern

 Let us use the grep command to determine whether the string 

 lines exists in the above file, and if so to print the line number.

                  data_file

              nl reads lines from

              the named file or

              standard input if

              no file is named,

              and reproduces the

              lines with numbers

              on the standard

              output.

 Please enter the command to look for lines containing the word 

 lines in the above file and print the line number(s).

 Enter here:   

 That is correct!

 You've got it on the 2nd try.

 Good, you understand the concept.

 Please use grep with the -n option for data_file

 Please type grep -n lines data_file

 I guess I must type this for you:

 PA: 2

FORGET1

 grep -n lines data_file

 Observe the result above.

              1:nl reads lines from

              6:lines with numbers